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Valen
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Joined: 07 Jul 2004
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Location: Sydney


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do not "measure the current of the battery"
it will be several hundred amps and will blow your multi meter.
V = IR
measure voltage and resistance, that will give you current.
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Post Wed Nov 21, 2007 8:56 am 
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Fish_in_a_Barrel



Joined: 30 Sep 2006
Posts: 673
Location: Perth, Western Australia


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measuring the resistance of the battery is also a bad idea. I did that once and blew a resister in my multimeter (back in the day there was no protection). Still seems to work fine with the charcoal in there Razz
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Post Wed Nov 21, 2007 10:10 am 
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cerberus3112



Joined: 05 Dec 2005
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Location: Mt Druitt,Sydney,NSW


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Hmm that would explain why my lsat ones terminals(prog thingies) well just melted of the plastic setion and the screen went black Rolling Eyes
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Post Wed Nov 21, 2007 3:15 pm 
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cerberus3112



Joined: 05 Dec 2005
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Location: Mt Druitt,Sydney,NSW


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yey time for me to ask more electrical questions

why do people say when you double the volts you 4 times the power out put of the motor?? does p = I V?? so doubleing volts would double out put not 4 times??

also to run a 400 watt drain for 1 hour at 12 volts you need 2000 amps right??
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Post Tue May 27, 2008 1:07 pm 
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Fish_in_a_Barrel



Joined: 30 Sep 2006
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V= IR

therefore I = V/R

and P=VI

substituting the above for I

P=V ( V/R)

-> P= V*V/R

so a double of the voltage for the same resistance is P = 2*2/R =4

which is 4 times the power compared to the original voltage.

Your second question is a bit ambiguous. To run the 400W load for 1 second will require I=P/V = 33.3A . Now to run the same load for an hour will require 33.3A delivered every second for an hour. This will require at minimum a 33.3Ah battery at C1 ratings. If you want to know the total amps consumed, then it's 33.3Amps/second * 3600 seconds/hour = 120000Amps delivered every hour.
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Post Tue May 27, 2008 1:40 pm 
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cerberus3112



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thanks for that i had the right idea but was applying it wrongly Embarassed
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Post Tue May 27, 2008 1:47 pm 
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Totaly_Recycled
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Ummm i don't get those figures at all?

a 400 watt load at 12 volts = 400 watts(watts equals watt hours) divided by 12volts equals 33.333333333 amps so thats 33.333333333 amps for one hour

where do you get 20,000 amps from? to run a 400 watt load at 12 volts for one second uses .555555556 amps so thats about half an amp a second not 33.3333333amps a second unless i missed something and you meant a 400 amp load which is 4800 watts at 12 volts but would only need to suply 400 amps at 12 volts for one hour .


Last edited by Totaly_Recycled on Fri May 30, 2008 10:50 pm; edited 1 time in total

Post Fri May 30, 2008 10:40 pm 
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Fish_in_a_Barrel



Joined: 30 Sep 2006
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Ummm, no one said 20,000... I said 120 000 Amps, and cerberus said 2 000.

The only reason I pointed my funny answer out was that 120 000 Amps for 1 second at 12V is the same amount of power as for 33.3A at 12V for an hour. I was trying to work out where the 2 000 came from.
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Post Fri May 30, 2008 10:46 pm 
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Totaly_Recycled
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sorry meant 120000 just typeo'd and missed the 1 on the front lol

Post Fri May 30, 2008 10:52 pm 
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Fish_in_a_Barrel



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Why are you getting 0.55A from?

Power is in Joules/second, Amps are in Coulombs/second and Volts are in Joules/Coulomb.

Watt hours doesn't equal watts, watt hours is a measure of energy, while watts is a measure of power.
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Post Fri May 30, 2008 11:07 pm 
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seanet1310



Joined: 08 Nov 2006
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Location: Adelaide


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Mike is right the amps is 33.3Amps which is coulombs per second.
watts (the unit of power) is joules/second
Watt hour is joules/ Second *3600
as there are 3600 seconds in an hour. my brain is 2 dead to test mikes acual canculations but the logic sounds about right 2 me.

Post Sat May 31, 2008 12:11 am 
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Philip
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Joined: 18 Jun 2004
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quote:
Originally posted by cerberus3112:
also to run a 400 watt drain for 1 hour at 12 volts
400 watts for a period of one hour is 400 watt hours.
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Post Sat May 31, 2008 8:23 am 
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cerberus3112



Joined: 05 Dec 2005
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thanks for all the info. I went back and re read my post and started laughing i don't even know how i got those numbers thanks for that.ill be a bit more careful next time i do calculations. Embarassed

i have no idea why I as trying to find out how many amps were used each second or even how many amps over the hour were used each second .... I blame bad thinking XD .(and a mix up with power and time)
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Post Sat May 31, 2008 1:28 pm 
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kkeerroo
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I think Totaly_Recycled was pointing out where you said 120000 Amps every hour rather than using the units A/hr or W/hr.

"If you want to know the total amps consumed, then it's 33.3Amps/second * 3600 seconds/hour = 120000Amps delivered every hour."

If he is drawing 33.3A then he would need a 33.3A/hr battery. That would equal 400W/hr or 1440kJ of energy per hour.
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Post Sat May 31, 2008 2:29 pm 
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Glen
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Joined: 16 Jun 2004
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needing some electronic help of my own,

tinkering with my brushless setups and both appear to have changable "govenor mode" settings. i tried it on my big inrunner and the only difference it seems to make is that it is less sensitive around the deadband when on?

any idea what a govenor mode does? does it just compensate for motor speed or something to that nature?
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Post Tue Jun 24, 2008 6:51 pm 
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