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assassin



Joined: 27 Jun 2004
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Here is 1 ton of force:



239 grams
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Post Thu Jul 30, 2009 6:20 pm 
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Knightrous
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What about the front links with a 250kg side load?
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Post Thu Jul 30, 2009 6:53 pm 
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assassin



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An arm by itself, no. But the whole linkage setup yes. I should do a test with the whole linkage setup, when I can. Good point, thx.
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Post Thu Jul 30, 2009 7:21 pm 
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Glen
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should try get a copy of ANYSIS. its like a mega version of cosmos with heaps more variables and the like. would be perfect for it.

(ill pm you if i can find a copy ;p)
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Post Thu Jul 30, 2009 7:25 pm 
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assassin



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Good!

I've asked this question a couple of pages back. Anyone know the approx force in weight you get from dropping a 30lbs object from 2 meters up?
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Post Thu Jul 30, 2009 7:34 pm 
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Nick
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Interesting! That seems to refute the whole concept of stress concentrating between the pivot points. Looking at the stresses.I'd think about tapering the arm at the rear and lightening the axle at the rear pivot, or taking it out completely.

Post Thu Jul 30, 2009 7:38 pm 
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assassin



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Thx Nick.

I answered my own question, about 267N(the dropping force) I think.
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Post Thu Jul 30, 2009 9:53 pm 
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Valen
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the force is dependant on how fast the thing stops.
If you drop a glass or something the force on the point that it contacts the ground would probably be in the order of tens of thousand kilograms. Dropping a pillow from the same height your probably going to get 2x the weight of the pillow as a force.

If your trying to work out how much force you need to throw an object into the air, you need to know how long you are accelerating it for in addition to the weight.

267 newtons is about 25kg, IE about the same as you would use when you pick your robot up off the floor, probably a bit less.
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Post Thu Jul 30, 2009 10:35 pm 
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assassin



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Thank you. What would be the force in KG of a 13.6KG object(combat robot) falling from 2 meters? About 380KG?
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Post Thu Jul 30, 2009 10:50 pm 
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Valen
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The force due to something falling onto something is undefined.
you need to know over what distance the falling object decelerates.
IE how much will the falling robot compress.
cobra, not very much.
boofhead, substantially more.
stealth, almost infinite.

Without some really really high end FEA (think the stuff used to simulate crash tests, because thats what your trying to do) you just aren't going to get a valid answer to that question.
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Post Thu Jul 30, 2009 10:56 pm 
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Bort
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But you could work out the 'stored' KE of a 13.6kg object from a height of 2 metres
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Post Thu Jul 30, 2009 11:18 pm 
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kkeerroo
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quote:
Originally posted by Bort:
But you could work out the 'stored' KE of a 13.6kg object from a height of 2 metres

you mean gravitational potential energy
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Post Fri Jul 31, 2009 8:39 am 
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Daniel
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I've done these calculation at uni where we had to calculated a person falling and attached to a rope and find out how much stress what on the tether. But that was a long time ago and I swear I forgot the calculations 10 minutes after doing it. After 6 years all I remember was it was called strain energy and in our calculation it worked out to be 4 times the standard weight, a 75kg person falling maybe 2m put 300kg of force on the tether, maybe. I might be wrong. I'll google it and see what I find

Post Fri Jul 31, 2009 2:01 pm 
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assassin



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Here is version 1, of the frame and linkages.


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Post Fri Jul 31, 2009 9:43 pm 
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assassin



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I ordered some aluminum today including the material for the ram. So hopefully I can start machining it next week, yay.
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Post Fri Jul 31, 2009 9:49 pm 
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